A string 25 cm long fixed at both ends and having a mass of 2.5 g is under tension . A pipe closed from one end is 40 cm long. When the string is set vibrating in its first overtone and the air in the pipe in its fundamental frequency, 8 beats per second are heard. It is observed that decreasing the tension in the string decreases the beat frequency. If the speed of sound in air is 320 m/s. Find tension in the string.
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(27.0400 N)
Frequency of first over tone of string = 
f 1 = 
fundamental frequency of close pipe
f 2 = 
= 
= 200 Hz
f 1 and f 2 produce 8 beats so f 1 = 200 + 8 or 200 – 8 on decreasing tension f 1 will decrease and beats decreases so it must be 200 + 8
208 = 
T = (208 × 25 × 10 –3 ) 2 = 27.04 N
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